Question

The hydraulic press shown in the figure is used to raise the mass $M$ through a height of $0.5cm$ by performing $500J$ of work at the small piston. The diameter of the large piston is $10cm$, while that of the smaller one is $2cm$ . The mass $M$ is

• A. $100kg$
• B. ${10}^{6}kg$
• C. ${10}^{3}kg$
• D. None of these

Answer 1

The correct option is D None of these

As work done by small position is equal to the work done on the mass $M$ as energy is conserved.

$\Rightarrow 500=M\times 5\times {10}^{-2}$

$\Rightarrow M=\frac{500\times {10}^2}{5}$

$\Rightarrow M={10}^{4}kg$

Hence, the answer is ${10}^{4}kg.$