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Question

The hydraulic press shown in the figure is used to raise the mass M through a height of 5.0 mm by performing 500 J of work at the small piston. The diameter of the large piston is 10 cm while that of the smaller one is 2 cm}. The mass M is

1443242_c5d53330302b4a9f80f0c0806e31a2b1.png

A
104kg
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B
103kg
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C
100 kg
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D
105kg
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Solution

The correct option is A 104kg
Given,

Work done, W=500J

Height, h=5mm=0.5×102m

We have,

W=Mgh

Then,

M=Wgh=50010×0.5×102=104kg

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