Question

The hydrogen electrode is dipped in a solution of $pH=3$ at ${25}^{\circ }C$. The potential of the cell would be (the value of $2.303\frac{RT}{F}$is $0.059V$

• A. 0.177 V
• B. – 0.177 V
• C. 0.087 V
• D. 0.059 V

Answer 1

The correct option is B – 0.177 V

Reduction potential of hydrogen electrode $=E_H=\frac{-2.303RT}{F}log\frac{1}{\left[H^{+}\right]}=-0.059pH=-0.059\times 3=-0.177V$