The hydrolysis of $N C l_{3}$ by water molecules produces:

N H_{2} O H + H O C l

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N H_{2} N H_{2} + H O

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N H_{4} O H + H O C l

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N H_{2} C l + H O C l

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Solution

The correct option is C $N H_{4} O H + H O C l$
The hydrolysis of NCl3 by water molecules :

$2 N C l_{3} + 8 H_{2} O \to 2 N H_{4} O H + 6 H O C l$

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Similar questions

N H_{4} O H

{C H}_{3} - C H = C H - C H O - -- \to H O C l

H C \equiv C H H O C l - ---- \to (e x c e s s) A

C H_{3} - C H O C l - ---- \to (e x c e s s) B

(O C l^{-})

H O C l \leftrightarrow H^{+} + O C L^{-} (k = 2.7 \times 10^{- 8} a t 20^{\circ} C)

O C l^{-}

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