The hydroxide ion concentration of a solution is $10^{- 6}$ mol/litre. The $p H$ of the solution is:

8

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6

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- 8

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Solution

The correct option is B $8$
$[O H^{-}] = 10^{- 6} M$ .
But $[H^{+}] [O H^{-}] = 10^{- 14}$ .
$[H^{+}] = \frac{10^{- 14}}{[O H^{-}]} = \frac{10^{- 14}}{10^{- 6}} M$ .
Hence, $[H^{+}] = 10^{- 8} M$ .
$p H = - l o g [H^{+}] = - l o g 10^{- 8} = 8$ .

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