The hydroxyl group at which carbon is involved in ring formation of glucose?

$C_{3}$

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$C_{4}$

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$C_{5}$

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$C_{6}$

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Solution

The correct option is C
$C_{5}$

Monosaccharides undergo intramolecular reaction to form cyclic hemiacetal structure. Generally in aldoses, the $C_{4}$ or $C_{5}$ carbon is involved in cyclisation. In glucose, the hemiacetal (six-membered ring) is formed between the $C H O$ group and the $O H$ group on the $C_{5}$ carbon.
Hence, (c) is correct.

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