The hyperbola x2a2−y2b2=1 passes through the point (2,3) and has the eccentricity 2. Then the transverse axis of the hyperbola has the length
A
1
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B
3
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C
2
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D
4
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Solution
The correct option is C2 Given hyperbola is, x2a2−y2b2=1 It passes through (2,3) 4a2−9b2=1..(1) Also eccentricity is 2, ⇒e2=1+b2a2=4⇒b2a2=3..(2) Solving (1) and (2) we get a=1,b=√3 Hence, length of transverse axis is =2a=2