Question

The hypotenuse of a right angled triangle is $26cm$ . If the sum of the other two sides is $34cm$, find the other two sides.

Answer 1

#1215097

$a+b=34cm$

$asweknow$ ${26}^2=a^2+b^2$

$or{26}^2=(34-b{)}^2+b^2$

$or676={34}^2+b^2-2.34.b+b^2$

$or676=1156+b^2-68b+b^2$

$or2b^2-68b-480=0$

$b^2-34b-240=0$

$b^2-24b-10b-240=0$

$b(b-24)-10(b-24)=0$

$(b-24)(b-10)=0$

$\therefore b=10orb=24$

$thena=34-b=34-10=24$

$thena=34-b=34-24=10$