Question

The hypotenuse of a right triangle is $26$ cm long. If one of the remaining two sides is $10$ cm long, find the length of the other side.

Answer 1

Let $\Delta ABC$ be a right angled triangle at $B$ where $AC=26cm$ and $AB=10cm$.

Using Pythagoras Theorem, in $\Delta ABC$,

$\Rightarrow A{C}^2=A{B}^2+B{C}^2$

$\Rightarrow {26}^2={10}^2+B{C}^2$

$\Rightarrow 676-100=B{C}^2$

$\therefore BC=\sqrt{576}=24$ cm

Thus, other side of the triangle is $24$ cm.