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Question

The I3 ion has

A
Five equatorial lone pairs on the central I atom and two axial bonding pairs in a trigonal bipyramidal arrangement
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B
Five equatorial lone pairs on the central I atom and two axial bonding pairs in a pentagonal bipyramidal arrangement
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C
Three equatorial lone pairs on the central I atom and two axial bonding pairs in a trigonal bipyramidal arrangement
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D
Two equatorial lone pairs on the central I atom and three axial bonding pairs in a trigonal bipyramidal arrangement
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Solution

The correct option is C Three equatorial lone pairs on the central I atom and two axial bonding pairs in a trigonal bipyramidal arrangement
Hybridisation of I3=12(7+2+1)=5=sp3d
So the geometry of the molecule is trigonal bipyramidal.
Number of bond pairs in I3=2
So, Number of lone pairs in I3=52=3
So the shape of the molecule is linear and there are three equatorial lone pairs on the central I atom and two axial bonding pairs in a trigonal bipyramidal arrangement.

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