Question

The I-V characteristic curve of an LED is

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

Here, $\text{K.E of electron}=\text{energy of the emitted photon}$

i.e. $eV=\frac{hc}{\lambda }$.

Also, ${\lambda }_{BLUE}<{\lambda }_{GREEN}$

LED works in forward biased mode and higher voltage give greater K.E to the electrons. Thus, emitting photons of lower wavelength
So voltage for Blue should be highest and that for red should be lowest.

Hence, $\left(A\right)$ is the correct answer.