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Question

The identical bodies A, B, and C each of mass 2kg, tied to an inextensible and massless string passing over a smooth pulley as shown in the figure. The tension in string connecting B to C will be:
3650_a13e5e1cab684929a0e3210b995a99b5.png

A
13 N
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B
0.13 N
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C
3.3 N
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D
zero
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Solution

The correct option is A 13 N
Let the tension between body B and C is T1,
The tension between body A and B is T2 ( because Pulley is smooth ) and 'a' is system acceleration
From FBD of Body C is shown in figure 1
mg - T1 = ma ........ 1

From FBD of Body B is shown in figure 2
mg + T1 - T2 = ma ............2

From FBD of Body A is shown in figure 3
T2 - mg = ma ............3

Add equation 2 and 3
T1 = 2 ma

put ma= T12 in equation 1
mg - T1= T12
T1 = 2 mg3
put m= 2 Kg ; g= 9.8
T1= 13.067 N 13 N

924434_3650_ans_b9c17c0eaeef4184bc3e1a5a32fb8f70.png

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