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Byju's Answer
Standard XII
Mathematics
Direction Cosines
The IE valu...
Question
The
I
E
value of,
A
l
(
g
)
⟶
A
l
+
(
g
)
+
e
is
577.5
k
J
m
o
l
−
1
and
Δ
H
for
A
l
(
g
)
⟶
A
l
3
+
(
g
)
+
3
e
is
5140
k
J
m
o
l
−
1
. If second and third
I
E
values are in the ratio
2
:
3
.
I
E
2
+
I
E
3
−
0.5
in
k
J
m
o
l
−
1
is:
Open in App
Solution
Given that
I
E
1
of
A
l
=
577.5
k
J
m
o
l
−
1
.
.
.
.
(
i
)
[
I
E
1
+
I
E
2
+
I
E
3
]
of
A
l
=
5140
k
J
m
o
l
−
1
.
.
.
.
(
i
i
)
Also given
I
E
2
=
(
2
/
3
)
I
E
3
.
.
.
.
.
(
i
i
i
)
solving eqs
(
i
)
,
(
i
i
)
,
(
i
i
i
)
I
E
2
=
1825
k
J
m
o
l
−
1
I
E
3
=
2737.5
k
J
m
o
l
−
1
I
E
2
+
I
E
3
=
1825
+
2737.5
=
4562.5
k
J
/
m
o
l
I
E
1
+
I
E
2
−
0.5
=
4562.5
−
0.5
=
4562
Suggest Corrections
0
Similar questions
Q.
The energy required to convert all atoms present in
1.2
g magnesium to
M
g
2
+
ions if
I
E
, and
I
E
2
of magnesium are
120
kJ
m
o
l
−
1
and
240
kJ
m
o
l
−
1
respectively.
Q.
The energy needed for
L
i
(
g
)
⟶
L
i
3
+
(
g
)
+
3
e
is
1.96
×
10
4
k
J
m
o
l
−
1
. If the first ionization energy of
L
i
is
520
k
J
m
o
l
−
1
, the second ionization energy for
L
i
in
3635
×
x
k
J
m
o
l
−
1
. Find
x
.
Given
I
E
1
for
H
=
2.18
×
10
−
18
k
J
m
o
l
−
1
.
Q.
Using the data given below, predict
Δ
H
for the reaction in
k
J
m
o
l
−
1
.
M
g
(
g
)
+
2
F
(
g
)
⟶
M
g
2
+
(
g
)
+
2
F
−
(
g
)
I
E
2
and
I
E
2
of
M
g
(
g
)
are
737.7
and
1451
k
J
m
o
l
−
1
.
E
A
1
for
F
(
g
)
is
−
328
k
J
m
o
l
−
1
.
[Take the nearest integer]
Q.
Use (IE) and (EA) listed below to determine whether the following process is endothermic or exothermic:
M
g
(
g
)
+
2
F
(
g
)
→
M
g
2
+
(
g
)
+
2
F
−
(
g
)
(
I
E
)
1
of
M
g
(
g
)
=
737.7
k
J
m
o
l
−
1
(
I
E
)
2
of
M
g
(
g
)
=
1451
k
J
m
o
l
−
1
(
E
A
)
of
F
(
g
)
=
−
328
k
J
m
o
l
−
1
Q.
The successive ionization energies for element
X
are given below:
I
E
1
=
250
kJ mol
−
1
I
E
2
=
820
kJ mol
−
1
I
E
3
=
1100
kJ mol
−
1
I
E
4
=
1400
kJ mol
−
1
Find out the number of valence electrons from the element
X
.
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