The II group precipitates soluble in yellow ammonium sulphide may be :

A s

S b

S n

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C u

H g

B i

C d

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Both (a) and (b)

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None of these

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Solution

The correct option is A $A s$ , $S b$ , $S n$
The II group precipitates soluble in yellow ammonium sulphide maybe $A s$ , $S b$ , $S n$ .

Yellow ammonium sulphide is a solvent for $A s$ , $S b$ , $S n$ sulphides.

Example: $A s_{2} S_{3} + 3 (N H_{4})_{2} S_{2} ⟶ 2 (N H_{4})_{3} A s S_{4} + S$

So, the correct option is $A$

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