The image distance of an object placed $10 c m$ in front of a thin lens of focal length $5 c m$ is

6.5 c m

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8.0 c m

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9.5 c m

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10.0 c m

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Solution

The correct option is B $10.0 c m$
As we know,
$\frac{1}{f} = \frac{1}{v} - \frac{1}{u} \Rightarrow \frac{1}{+ 5} = \frac{1}{v} - \frac{1}{(- 10)} \Rightarrow v = 10 c m$

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An object is placed at 30 cm in front of the convex lens of focal length 10 cm. The distance of the image from the lens is + ___ cm.

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