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Question

The image distance of an object placed 10cm in front of a thin lens of focal length +5cm ______

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Solution


Given:
the object distance u = -10 cm
the focal length f = 5 cm
For a lens ,
1v1u=1f
1v = 1u + 1f = 110 + 15= 110
v = 10 cm
Hence , the image distance = 10 cm

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