The correct option is
B certainly real if the object is virtual.
Using mirror equation,
1v+1u=1f
1v=1f−1u
For concave mirror, focal length is negative. Hence, f<0
For a virtual object, object distance is positive. Hence uv>0
From above, it can be observed that image distance v is negative when object is virtual. Since image distance is negative, it is formed by real intersection of rays and image is real.
For a real object, object distance is negative. Hence ur<0
In this case, image distance v may be positive or negative depending on the location of object.
Hence, only option C is correct.