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Question

The image of a point (3t+1,14t), tR{0} in a line, lies on 3x4y+1=0. Then the slope of line(s) is (are)

A
7
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B
7
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C
17
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D
17
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Solution

The correct option is D 17
(3t+1,14t) represents L1:4x+3y7=0 and L2:3x4y+1=0.
So, the image of every point on L1 about a line lies on the line L2
The line must be the angle bisector of L1 and L2.

The angle bisectors of L1 and L2 are 7xy6=0 and x+7y8=0

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