Question

The image of construction of two tangents inclined at ${60}^{\circ }$ drawn to a circle of radius of 4cm is given below.

Arrange the steps of construction the in correct order.
1.Take a point A on the circumerence of the circle and join OA. Draw a perpendicular to OA at point A.
2.Draw radius OC, making an angle of ${120}^{\circ }({180}^{\circ }-{60}^{\circ })$.
3.Draw a circle of radius 4cm and mark its centre as O.
4.Draw a perpendicular to OC at point C.Let both the perpendiculars intersect at point P. PA and PC are the required tangents inclined at an angle of ${60}^{\circ }$.

• A. 1,4,3,2
• B. 3,2,1,4
• C. 1,2,3,4
• D. 3,1,2,4

Answer 1

The correct option is D 3,1,2,4

1.Draw a circle of radius 4cm and mark its centre as O.
2.Take a point A on the circumerence of the circle and join OA. Draw a perpendicular to OA at point A.
3. Draw radius OC, making an angle of ${120}^{\circ }({180}^{\circ }-{60}^{\circ })$.
4.Draw a perpendicular to OC at point C. Let both the perpendicular intersect at point P. PA and PC are the required tangents inclined at an angle of ${60}^{\circ }$.
Then we get,