Question

The image of point $P$ when viewed from top of the slabs will be :

• A. $2.0cm$ below $P$
• B. $1.5cm$ above $P$
• C. $2.0cm$ above $P$
• D. $1cm$ above $P$

Answer 1

The correct option is D $1cm$ above $P$

Shift observed due to refraction is $t(1-\frac{1}{\mu })=2\times 1.5(1-\frac{2}{3})=1cm$
Hence, image of point $P$ when viewed from top of the slabs will be $1cm$ above $P$.