wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The image of the needle placed 45 cm from a lens is formed on a screen placed 90 cm on the other side of the lens. The displacement of the image, if the needle is moved by 5.0 cm away from the lens is

A
10 cm, toward the lens
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
15 cm, away from the lens
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
15 cm, towards the lens
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
10 cm, away from the lens
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 15 cm, towards the lens
Here, u = -45 cm, v = 90 cm
1f=1v1u=190+145=130f=30cm
when the needle is move 5 cm away from the lens,
u=-(45 + 5) = -50 cm
1v=1f+1u=130+1(50)=2150=v=75cm
Displacement of image = v-v' =90-75= 15 cm, towards the lens

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Lens Formula, Magnification and Power of Lens
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon