The image of the point P(3, 5) with respect to the line y = x is the point Q and the image of Q with respect to the line y = 0 is the point R(a, b), then (a, b) =
(5, –3)
Let (x1, y1) be the image of the point P (3, 5) with respect to the line y = x.
Then, x1 = 5, y1 = 3.
∴ Q = (5, 3)
Since the image of the point Q(5, 3) with respect to the line y = 0 is (a, b)
∴ a = 5 and b = –3
∴ (a, b) = (5, –3)