wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The imaginary angular velocity of the earth for which the effective acceleration due to gravity at the equator shall be zero is equal to

A
1.25×103 rad/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2.50×103 rad/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3.75×103 rad/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5.0×103 rad/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 1.25×103 rad/s
We know,

g=g(1Rω2gcos2λ)

At the equator,

λ=0 and cosλ=1

Let g be the acceleration due to gravity when the earth were supposed to be at rest. In presence of earth's rotation on acceleration due to gravity at the equator is given by,

g=gReω2

where ω is the angular velocity of the earth. For g,=0, the above relation becomes,

ω=gRe=10ms2(6400×103)m=1.25×103rad/s

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Acceleration Due to Gravity
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon