the impedance of a series circuit consists of $3$ ohm resistance and $4$ ohm resistance

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Solution

$Z = \sqrt{R^{2} + X^{2}} \sqrt{4^{2} {+ 3}^{2}} = 5$
$c o s φ = \frac{R}{Z} = \frac{3}{5} = 0.6$

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the impedance of a series circuit consists of 3 ohm resistance and 4ohm resistance

Z=√R2+X2√42+32=5cosφ=RZ=35=0.6

the impedance of a series circuit consists of $3$ ohm resistance and $4$ ohm resistance

$Z = \sqrt{R^{2} + X^{2}} \sqrt{4^{2} {+ 3}^{2}} = 5$
$c o s φ = \frac{R}{Z} = \frac{3}{5} = 0.6$