Question

The impedance of coaxial cable, when its inductance is 0.40 $\mu$H and capacitance is 1 $\times {10}^{-11}$ F, can be

• A. 2 $\times {10}^2\Omega$
• B. 100 $\Omega$
• C. 3 $\times {10}^3\Omega$
• D. 3 $\times {10}^{-2}\Omega$

Answer 1

The correct option is A 2 $\times {10}^2\Omega$

Using Z = $\sqrt{\frac{L}{C}}$ we get Z = $\sqrt{\frac{0.40\times {10}^{-6}}{{10}^{-11}}}=2\times {10}^2\Omega$