The correct option is D √9524 Ω
P has R1=32Ω C1=1μF
Q has R2=68Ω L2=4.9mH
Total impedance of the series combination of P and Q :
Z=R1+R2+jLω−j1Cω
The frequency is adjusted so that maximum current flows in P and Q. that is, frequency is adjusted to have minimum total series impedance. Total series impedance will be minimum when the reactance of L and C cancel each other. Therefore,
ω=1√LC=1000007rad/s
Therefore at maximum current, impedance of Q=R2+jLω=68+70j=√9524Ω