Question

The improper fraction $\frac{33}{4}$ in the form of a mixed fraction is:

• A. $3\frac{8}{4}$
• B. $8\frac{1}{4}$
• C. $4\frac{7}{8}$
• D. $4\frac{1}{8}$

Answer 1

The correct option is B $8\frac{1}{4}$

$=\frac{33}{4}$
$=\frac{32+1}{4}$
$=\frac{32}{4}+\frac{1}{4}$
$=8+\frac{1}{4}$
$=8\frac{1}{4}$