The impulse response of an discrete time LTI system is given by h-n- -3- -n-1- -2- -n-2- -n-3- The value of Hz at z - 1 is

H[n] =3δ [n 1] +2δ [n 2]+δ [n 3] nbsp; H(z) = 3Z^ 1 + 2Z^ 2+Z^ 3 nbsp; H(1) = 3 × 1 + 2 ×1 + 1 = 6 nbsp; ...

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Binding Energy

The impulse r...

Question

The impulse response of an discrete time LTI system is given by
$h [n] = 3 δ [n - 1] + 2 δ [n - 2] + δ [n - 3]$
The value of $H (z)$ at $z = 1$ is

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A discrete-time system 'S' with impulse response h [n] = {(\frac{1}{3})}^{n} u [n] . If system difference equation is h [n] - k h [n - 1] = δ [n], then the value of k

h (n) = {(\frac{1}{5})}^{n} u (n) .

h (n) - C . h (n - 1) = δ (n),

x (n) = {(\frac{1}{2})}^{n} u (n) - \frac{1}{4} {(\frac{1}{2})}^{n - 1} u (n - 1)

y (n) = {(\frac{1}{3})}^{n} u (n)

h (n) = b^{n} u (n + 1), | b | < 1

H (z) = \frac{z^{2}}{(z - \frac{1}{2}) (z - \frac{1}{4})}

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