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Question

The impure 6 g of NaCl is dissolved in water and then treated with excess of silver nitrate solution. The weight of precipitate of silver chloride is found to be 14.35 g. The % purity of NaCl solution would be :

A
97.5%
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B
87.5%
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C
77.5%
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D
67.5%
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Solution

The correct option is A 97.5%
The reaction that takes place is
NaCl+AgNO3AgCl+NaNO3
143.5 of AgCl is produced from 58.5 g NaCl14 g of AgCl will produce from58.5×14.35143.5=5.85 g
This is the amount of NaCl in common salt.% purity=5.856×100=97.5%

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