The impure 6g of NaCl is dissolved in water and then treated with excess of silver nitrate solution. The weight of precipitate of silver chloride is found to be 14.35g. The % purity of NaCl solution would be :
A
97.5%
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B
87.5%
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C
77.5%
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D
67.5%
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Solution
The correct option is A97.5% The reaction that takes place is NaCl+AgNO3→AgCl↓+NaNO3 ∵143.5ofAgClis produced from58.5gNaCl∴14gof AgCl will produce from58.5×14.35143.5=5.85g This is the amount of NaCl in common salt.%purity=5.856×100=97.5%