The incenter of the triangle formed by $(1, 2), (3, 4)$ and $(2, 3)$ is

D o e s n o t e x i s t

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(- 2, 3)

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(2, - 3)

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(3, 3)

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Solution

The correct option is A $D o e s n o t e x i s t$
Take $(1, 2) (3, 4)$ and $(2, 3)$ as $(x 1, y 1), (x 2, y 2)$ and $(x 3, y 3)$ . Apply cetroid
formula $x 1 + x 2 + x 3 / 3$ and $y 1 + y 2 + y 3 / 3$
$1 + 3 + 2 / 3, 2 + 4 + 3 / 3 = 6 / 3$
$, 9 / 3 = 2, 3$

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Similar questions

3, 3 + \sqrt{2}, 3 + 2 \sqrt{2}, 3 + 3 \sqrt{2}, . . .

Q. Is the given sequence

3, 3 + \sqrt{2}, 3 + 2 \sqrt{2}, 3 + 3 \sqrt{2}

form an APs? If it forms an AP, find the common difference

d

and write the next three terms.

Q. The circumcenter of the triangle formed by

(- 2, 3) (2, - 1)

and

(4, 0)

Question 4 (v)
Which of the following are APs? If they form an A.P. find the common difference d and write three more terms.
(v) $3, 3 + \sqrt{2}, 3 + 2 \sqrt{2}, 3 + 3 \sqrt{2}$

Consider A = {1, 2, 3, 4} and B = {2, 3, 5, 9}. Is the relation f = {(1, 2), (2, 3), (3, 3), (3, 5)} a function from A to B?

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The incenter of the triangle formed by (1,2),(3,4) and (2,3) is

The correct option is A Does not existTake (1,2)(3,4) and (2,3) as (x1,y1),(x2,y2) and (x3,y3). Apply cetroidformula x1+x2+x3/3 and y1+y2+y3/31+3+2/3,2+4+3/3=6/3,9/3=2,3

The incenter of the triangle formed by $(1, 2), (3, 4)$ and $(2, 3)$ is

The correct option is A $D o e s n o t e x i s t$
Take $(1, 2) (3, 4)$ and $(2, 3)$ as $(x 1, y 1), (x 2, y 2)$ and $(x 3, y 3)$ . Apply cetroid
formula $x 1 + x 2 + x 3 / 3$ and $y 1 + y 2 + y 3 / 3$
$1 + 3 + 2 / 3, 2 + 4 + 3 / 3 = 6 / 3$
$, 9 / 3 = 2, 3$