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Question

The incentre of the triangle formed by (0,0,0),(3,0,0),(0,3,0).

A
(34,34,0)
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B
(1,34,0)
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C
(0,1,1)
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D
(1,1,1)
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Solution

The correct option is D (1,34,0)
using formula incenter x=ax1+bx2+cx3a+b+c

y=ay1+by2+cy3a+b+c
z=az1+bz2+cx3a+b+c
a=5 x=5(0)+4(3)+3(0)5+4+3 ; x=1


b=4 y=5(0)+4(0)+3(3)5+4+3 ; y=34


c=3 z=5(0)+4(0)+3(0)5+4+3 ; z=0

incentre =(1,34,0)

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