The incentre of the triangle formed by -0- 0- -5-12- -16- 12- is- -9- 7-7-9-9-7-7-9-

The correct option is D (7,9) Obviously a = 11, b = 20, c = 13. Hence incentre is (11 × 0 + 20 × 5 + 13 × 16/11 + 20 + 13, 11 × 0 + 20 × 12 + 13 × 12/11 + 20 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Incentre

The incentre ...

Question

The incentre of the triangle formed by (0, 0), (5,12), (16, 12) is

(7,9)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(9,7)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(-9, 7)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(-7,9)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
(7,9)

Obviously a = 11, b = 20, c = 13.

Hence incentre is

$(\frac{11 \times 0 + 20 \times 5 + 13 \times 16}{11 + 20 + 13}, \frac{11 \times 0 + 20 \times 12 + 13 \times 12}{11 + 20 + 13})$

i.e. (7, 9).

Suggest Corrections

Similar questions

Q. The incentre of the triangle formed by

(0, 0), (5, 12), (16, 12)

is:

Q. The incentre of the triangle formed by (0, 0), (5, 12), (16, 12) is

Q. The incentre of the triangle formed by

(0, 0, 0), (3, 0, 0), (0, 3, 0)

The reflection of point (-7, -9) through Y axis would be___

The image of the point (-7, -9) when refleceted in the Y axis is ___

Join BYJU'S Learning Program

The incentre of the triangle formed by (0, 0), (5,12), (16, 12) is

The correct option is A (7,9) Obviously a = 11, b = 20, c = 13. Hence incentre is (11×0+20×5+13×1611+20+13,11×0+20×12+13×1211+20+13) i.e. (7, 9).

The correct option is A
(7,9)

Obviously a = 11, b = 20, c = 13.

Hence incentre is

$(\frac{11 \times 0 + 20 \times 5 + 13 \times 16}{11 + 20 + 13}, \frac{11 \times 0 + 20 \times 12 + 13 \times 12}{11 + 20 + 13})$

i.e. (7, 9).