Question

The incentre of the triangle formed by (0, 0), (5,12), (16, 12) is

• A. (7,9)
• B. (9,7)
• C. (-9, 7)
• D. (-7,9)

Answer 1

The correct option is A

(7,9)

Obviously a = 11, b = 20, c = 13.

Hence incentre is

$(\frac{11\times 0+20\times 5+13\times 16}{11+20+13},\frac{11\times 0+20\times 12+13\times 12}{11+20+13})$

i.e. (7, 9).