The incentre of the triangle with vertices (1,√3),(0,0) and (2,0) is
A
(1,√32)
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B
(23,1√3)
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C
(23,√32)
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D
(1,1√3)
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Solution
The correct option is C(1,1√3) Since, the given triangle is an equilateral triangle. Therefore, incentre coincide with the centroid. ie, (1+0+23,√3+0+03)=(1,1√3)