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Question

The incident intensity on a horizontal surface at sea level from the sun is about 1kWm2. Assuming that 50 per cent of this intensity is reflected and 50 per cent is absorbed, determine the radiation pressure on this horizontal surface (in pascals).

A
8.2×102
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B
5×106
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C
3×105
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D
6×105
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Solution

The correct option is B 5×106
Given: I=1000 Wm2
As 50 percent of light is reflected, thus e=0.5

Radiation pressure, P=(1+e)Ic

P=(1+0.5)×10003×108=5×106 Pa

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