Question

The incident voltage wave on a certain loss less transmission line for which $Z_0=50\Omega$ and $v_p=2\times {10}^{8}m/sec$

is $V^{+}(z.t)=200cos(\omega t-\pi z)Volt.$ The angular frequency ${}^{\prime }{\omega }^{\prime }$ (in rad/sec) is _________ $\times {10}^8$

• A. 6.28
• B. 5.36
• C. 3.55
• D. 4.28

Answer 1

The correct option is A 6.28

$\beta =\pi =\frac{\omega }{V_P}\Rightarrow \omega =\pi \times 2\times {10}^8=6.28\times {10}^{8}rad/sec$