Question

The inclination of the line x – y + 3 = 0 with positive direction of x-axis, is
(a) 45°
(b) 135°
(c) –45°
(d) –135°

Answer 1

For line x − y + 3 = 0
Inclination with position direction of x-axis is given by ${\tan }^{-1}\left(\frac{-b}{a}\right)$ where ax + bx + c = 0 is the line
$$\begin{gathered} \mathrm{i}.\mathrm{e}.\mathrm{inclination}\mathrm{is}{\tan }^{-1}\frac{\left(+1\right)}{1} \\ ={\tan }^{-1}1 \\ =\frac{\mathrm{\pi }}{4}=45° \end{gathered}$$

Hence the correct answer is option A.