Question

The income of $A$ is $20\%$ higher than that of $B$. The income of $B$ is $25\%$ less than that of $C$. What percent less is $A$'s income from $C$'s income?

• A. $7\%$
• B. $8\%$
• C. $10\%$
• D. $12.5\%$

Answer 1

Answer: (C)

$10\%$

We take $B$'s income $=$ Rs. $100$.

Then $A$'s income $=$ Rs. $(100+20)=$ Rs. $120$ by the given condition.

Also $B$'s income is $25\%$ less than that of $C$.

i.e $B$'s income $=(100-25)\%=75\%$ of $C$'s income.

$\therefore$ $C$'s income $=$ Rs. $\frac{100}{75}\times 100=$ Rs. $\frac{400}{3}$

$\therefore$ the income of $A$ is less than that of $C$

$=$ Rs. $(\frac{400}{3}-120)=$ Rs. $\frac{40}{3}.$

So the p.c of the shortage in $A$'s income from $C$'s income

$=$ $\frac{\frac{40}{3}}{\frac{400}{3}}\times 100=10$ p.c.

Ans- Option C.