The income of a person is Rs. 300,000 in the first year and he receives an increase of Rs. 10000 to his income per year for the next 19 years. Find the total amount, he received in 20 years.

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Solution

First year the person income is : 300,000

Second year his income will be : 300,000 + 10,000=310,000

This way he receives the amount after 20 years will be:

300,000 + 310,000 + .... + 490,000

This is an A.P with first term a = 300000 and common difference d = 10,000

Therefore

$S = \frac{20}{2} [2. (300000) + (20 - 1) 10000]$

= 10[600000 + 190000]

=7900000

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