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Faraday's Law

The incorrect...

Question

The incorrect hydrated radius order is:

L i_{(a q)}^{+} < B e_{(a q)}^{2 +}

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N a_{(a q)}^{+} < A l_{(a q)}^{3 +}

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I_{(a q)}^{-} > C l_{(a q)}^{-}

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B a_{(a q)}^{2 +} < C a_{(a q)}^{2 +}

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Solution

The correct option is D $I_{(a q)}^{-} > C l_{(a q)}^{-}$
The incorrect hydrated radius order is $I_{(a q)}^{-} > C l_{(a q)}^{-}$ .
The correct order of hydrated radius is $I_{(a q)}^{-} < C l_{(a q)}^{-}$ .
Higher is the charge and lower is the size, higher is the extent of hydration and higher is the hydrated radius.

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N a C l (s) + a q ⟶ N a^{\oplus} (a q) + C l^{⊖}

Δ H = 3.9 k J

N a^{\oplus} (g) + C l^{⊖} (g) ⟶ N a C l (s) Δ H = - 788 k J

C l^{⊖} (g) + a q ⟶ C l^{⊖} (a q) Δ H = - 394.1 k J

N a^{\oplus}

{C s}_{a q}^{+} < {R b}_{a q}^{+} < K_{a q}^{+} < {N a}_{a q}^{+}

A g^{+}

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N O_{3}

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N a^{+} (a q) + C l (a q) + A g^{+} (a q) + N O_{3} (a q) ⇌ A g C l (s) + N a^{+} (a q) + N O_{3} (a q) Δ H = 65.9 k J

ionic species having largest size:

A. Li+(g)

B.Na+ (aq)

C. Rb+(aq)

D. Li+(aq)

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N a^{+} (a q) + C l^{-} (a q) + A g^{+} (a q) + N O_{3}^{-} (a q) ⇌ A g C l (s) + N a^{+} (a q) + N O_{3}^{-} (a q) Δ H = - 65.9 k J

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