The INCORRECT match in the following is :

$Δ G^{0} < 0, K < 1$

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$Δ G^{0} < 0, K = 1$

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Δ G^{0} > 0, K < 1

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Δ G^{0} < 0, K > 1

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Solution

The correct option is A
$Δ G^{0} < 0, K < 1$

$Δ G = Δ G^{0} + R T I n k$
At equilibrium,
$\Rightarrow Δ G^{0} = - R T I n K = 0$

$- R T I n K < 0$

$R T I n K > 0$

$I n K > 0$

$\Rightarrow K > 1$
Hence, correct option is (a).

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