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Gibbs Free Energy & Spontaneity

The INCORRECT...

Question

The INCORRECT match in the following is :

Δ G^{0} < 0, K < 1

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Δ G^{0} < 0, K = 1

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Δ G^{0} > 0, K < 1

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Δ G^{0} < 0, K > 1

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Solution

The correct option is A $Δ G^{0} < 0, K < 1$
We know,
$Δ G = Δ G^{0} + R T l n K$

At equilibrium,

$Δ G = Δ G^{0} + R T l n K = 0$
$\Rightarrow Δ G^{0} = - R T l n K$

$- R T l n K < 0$
$R T l n K > 0$

$l n K > 0$

$\Rightarrow K > 1$

Suggest Corrections

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