. The incorrect order of solubility in water is

C a (O H)_{2} < S r (O H)_{2} < B a (O H)_{2}

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L i_{2} C O_{3} < N a_{2} C O_{3} < K_{2} C O_{3}

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C s N O_{3} < R b N O_{3} < K N O_{3}

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B a S_{2} O_{3} < M g S_{2} O_{3} < C a S_{2} O_{3}

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Solution

The correct option is B $C a (O H)_{2} < S r (O H)_{2} < B a (O H)_{2}$
$C a (O H)_{2} < S r (O H)_{2} < B a (O H)_{2}$
the order of incorrect is A

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Similar questions

The correct order of the O - O bond length in $O_{2}$ , $H_{2} O_{2}$ and $O_{3}$ is

B a (O H)_{2} > S r (O H)_{2} > C a (O H)_{2} > B e (O H)_{2}

H_{2} O ?

(1) B e S O_{4} > M g S O_{4} > C a S O_{4} > B a S O_{4}

(2) B e (O H)_{2} > M g (O H)_{2} > C a (O H)_{2} > B a (O H)_{2}

(3) L i O H < N a O H < K O H < R b O H

(4) L i_{2} C O_{3} < N a_{2} C O_{3} < K_{2} C O_{3} < R b_{2} C O_{3}

O - O

O_{2}, H_{2} O_{2}, O_{3}

A

B

3

A B = O_{3}

O_{3}

3

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