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Le Chatelier's Principle for Del N Equals to 0

The incorrect...

Question

The incorrect statement among the following, for this reaction, is:

Decrease in the total pressure will result in formation of more moles of gaseous

X

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At the start of the reaction, dissociation of gaseous

X_{2}

takes place spontaneously

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β_{e q u i l i b r i u m} = 0.7

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K_{c} < 1

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Solution

The correct option is C $β_{e q u i l i b r i u m} = 0.7$
(A) Correct statement.
As on decrease in pressure reaction move in direction where no. of gaseous molecules increase.

(B) Correct statement
At the start of reaction $Q_{P} < K_{P}$ so dissociation of $X_{2}$ take place spontaneousely.

(C) Incorrect statement as $K_{P} = \frac{8 β^{2} e q}{4 - β^{2} e q} = \frac{8 \times (0.7)^{2}}{4 - (0.7)^{2}}$
$> 1$

(D) Correct statement.
As $Δ G^{0} > 0$ & $Δ G^{0} = - R T l n K_{P}$

$Δ G^{0} > 1$ , So $K_{P}$ should be less than 1.

So $K < 1$

$K_{P} = K_{C} (R T)^{Δ n_{g}}$ (RT > 1)

$K_{C} = \frac{K_{P}}{R T}$

$K_{C} < K_{P}$

So, $K_{C} < 1$

Suggest Corrections

Similar questions

Q. Thermal decomposition of gaseous

X_{2}

to gaseous X at 298 K takes place according to the following equation:

X_{2} (g) ⇌ 2 X (g)

The standard reaction Gibbs energy,

Δ G^{o},

of this reaction is positive. At the start of the reaction, there is one moe of

X_{2}

and no X. As the reaction proceeds, the number of moles of X formed is given by

β,

Thus,

β_{e q u i l i b r i u m}

is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.
(Given: R = 0.083 L bar

K^{- 1} m o l^{- 1}

)

The Incorrect statement among the following, for this reaction is

Q. Thermal decomposition of gaseous

X_{2}

to gaseous X at 298 K takes place according to the following equation:

X_{2} (g) ⇌ 2 X (g)

The standard reaction Gibbs energy,

Δ_{r} G^{0},

of this reaction is positive. At the start of the reaction, there is one mole of

X_{2}

and no X. As the reaction proceeds, the number of moles of X formed is given by

β

. Thus,

β_{e q u i l i b r i u m}

is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally. (Given: R = 0.083 L bar

K^{- 1} m o l^{- 1}

).

The INCORRECT statement among the following, for this reaction is:

Q. Thermal decomposition of gaseous

X_{2}

to gaseous X at 298 K takes place according to the following equation:

X_{2} (g) ⇌ 2 X (g)

The standard reaction Gibbs energy,

Δ_{r} G^{0},

of this reaction is positive. At the start of the reaction, there is one mole of

X_{2}

and no X. As the reaction proceeds, the number of moles of X formed is given by

β

. Thus,

β_{e q u i l i b r i u m}

is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally. (Given: R = 0.083 L bar

K^{- 1} m o l^{- 1}

)

The equilibrium constant

K_{p}

for this reaction at 298 K, in terms of

β_{e q u i l i b r i u m},

is:

Consider the following statements:

(I) An increase in pressure (caused by decrease in volume) at equilibrium results in increase in molar concentration of each gaseous substance involved.

(II) An increase in pressure (caused by decrease in volume) at equilibrium results in increase in no. of moles of each gaseous substance involved.

(III) For the reaction

A (s) ⇌ B (g) + C (g)

at constant temperature, total pressure at equilibrium (of

B (g)

C (g)

) is not affected by changing the volume of container.

(IV)

H_{2} O (l) ⇌ H_{2} O (g)

on temperature increase,

K_{p}

of this reaction is increased.

Tick the correct statement(s)

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

is a gaseous phase equilibrium reaction taking place in a

5

litre flask at

1 a t m

. For this :

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