Question

The incorrect statement regarding 'X' in the given reaction is:
$B{F}_3+LiAl{H}_4\stackrel{Ether}{\to }\left(X\right)+LiF+Al{F}_3$

• A. Twelve electrons are involved in bonding
• B. Four, 2c-2e bonds are present in X
• C. Two, 3c-2e bonds are present in X
• D. X does not react with $N{H}_3$

Answer 1

The correct option is D X does not react with $N{H}_3$

$B{F}_3+LiAl{H}_4\stackrel{Ether}{\to }\underset{\left(X\right)}{B_2{H}_6}+LiF+Al{F}_3$

$N{H}_3$ reacts with $B_2{H}_6$ according to the following reaction:
$B_2{H}_6+2N{H}_3\stackrel{warm}{\to }[B{H}_2.2N{H}_3{]}^{+}.[B{H}_4{]}^{-}\stackrel{200{}^{o}C}{\to }{B}_3{N}_3{H}_6$