The increase in the speed of sound, on increasing the temperature of the medium by $10^{\circ} C$ , will be

600 m s^{- 1}

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6 m s^{- 1}

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0.61 m s^{- 1}

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60 m s^{- 1}

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Solution

The correct option is C $6 m s^{- 1}$
The speed of sound is given approximately by

$V$ $=$ $331.4 + 0.6 T$
differentiating above equation gives

$Δ V$ $=$ $0.6 Δ T$

so $Δ$ $V$ $=$ $0.6 * 10$ $=$ $6 m / s e c$

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The increase in the speed of sound, on increasing the temperature of the medium by 10∘ C, will be

The correct option is C 6 ms−1The speed of sound is given approximately byV=331.4+0.6T331.4+0.6Tdifferentiating above equation gives ΔV=0.6ΔTso ΔV=0.6∗10=6m/sec

The increase in the speed of sound, on increasing the temperature of the medium by $10^{\circ} C$ , will be

The correct option is C $6 m s^{- 1}$
The speed of sound is given approximately by

$V$ $=$ $331.4 + 0.6 T$
differentiating above equation gives

$Δ V$ $=$ $0.6 Δ T$

so $Δ$ $V$ $=$ $0.6 * 10$ $=$ $6 m / s e c$