Question

The increase in velocity of a freely falling body in one second is

• A. $9.8$ $m{s}^{-2}$
• B. 9.8 $m{s}^{-1}$
• C. -9.8 $m{s}^{-2}$
• D. -9.8 $m{s}^{-1}$

Answer 1

The correct option is B

9.8 $m{s}^{-1}$

Step 1: Calculating the velocity of a freely falling body

1. For a freely falling body, we can say that the body is falling under gravity.
2. The acceleration attained by the body while falling freely under gravity is called acceleration due to gravity.
3. Acceleration due to gravity is represented as $g$whose value is$9.8$$m{s}^{-2}$.
4. As per the definition of acceleration, $acceleration=\frac{velocity}{time}$
5. Putting the value of acceleration $\left(g\right)$ and time $\left(t=1sec\right)$we get $velocity=g\times t$

$\Rightarrow v=9.8m/s^2\times 1s$

$\Rightarrow v=9.8m/s$

Hence,

the velocity of the freely falling body in one second is$9.8m/s$.