Question

The increase in volume of air, when temperature of 600ml of it, is increased from ${27}^{o}Cto{47}^{o}C$ under constant pressure is:

• A. 20 mL
• B. 80 mL
• C. 40 mL
• D. 500 mL

Answer 1

The correct option is C 40 mL

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$
so $V_2=\frac{T_2}{T_1}.V_1=\frac{320}{300}\times 600ml=640ml$
so increment $=(640-600)ml=$40 ml