The $%$ increase of s-character in the hybrid orbitals of carbon in $C H_{4}, C_{2} H_{4}, C_{2} H_{2}$ follow the order:

C H_{4} > C_{2} H_{4} > C_{2} H_{2}

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C_{2} H_{4} < C H_{4} < C_{2} H_{2}

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C H_{4} < C_{2} H_{4} < C_{2} H_{2}

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C_{2} H_{4} < C_{2} H_{2} < C H_{4}

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Solution

The correct option is C $C H_{4} < C_{2} H_{4} < C_{2} H_{2}$
Option C is correct.

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Similar questions

C a C_{2} + H_{2} O \to A H_{2} S O_{4} / H g S O_{4} - -------- \to B

.

Identify A and B in the given reaction

Find the oxidation number of elements in each case :

C

C H_{4}, C_{2} H_{6}, C_{3} H_{8}, C_{2} H_{4}, C_{2} H_{2}, H_{2} C_{2} O_{4}

and

C O_{2}

Q. Determine equivalent weight of carbon in the following :
(a)

C + O_{2} \to C O_{2}

(b)

C + 2 H_{2} \to C H_{4}

(c)

2 C + H_{2} \to C_{2} H_{2}

(d)

2 C + 2 H_{2} \to C_{2} H_{4}

Q. A mixture of

C H_{4}, C_{2} H_{4}

and

C_{2} H_{2}

gaseous are passed through a Wolfbottle containing ammonical cuprous chloride. The gas coming out is:

100 ml of $C H_{4}$ and $C_{2} H_{2}$ were exploded with excess of $O_{2}$ . After explosion and cooling, the mixture was treated with KOH, where a reduction of 165 ml was observed. Therefore the composition of the mixture is -

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The % increase of s-character in the hybrid orbitals of carbon in CH4,C2H4,C2H2 follow the order:

The correct option is C CH4<C2H4<C2H2Option C is correct.

The $%$ increase of s-character in the hybrid orbitals of carbon in $C H_{4}, C_{2} H_{4}, C_{2} H_{2}$ follow the order:

The correct option is C $C H_{4} < C_{2} H_{4} < C_{2} H_{2}$
Option C is correct.