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Question

The increasing d-character in hybridisation of Xe in XeF2,XeF4,XeF6 is :

A
XeF2<XeF4<XeF6
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B
XeF4<XeF2<XeF6
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C
XeF6<XeF4<XeF2
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D
XeF2<XeF6<XeF4
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Solution

The correct option is A XeF2<XeF4<XeF6
XeF2=2+822
=2+3 sp3d
XeF4=4+842
=4+2 sp3d2
XeF6=6+862
=6+1 sp3d3
increasing d character
XeF6>XeF4>XeF2

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